The server encountered an internal error () that prevented it from fulfillin

码拜

9年 ago

HTTP Status 500 – ——————————————————————————– type Exception report message description The server encountered an internal error () that prevented it from fulfilling this request. exception org.apache.jasper.JasperException: An exception occurred processing JSP page /register.jsp at line 9 6: if (request.getParameter(“login”) != null) { 7: String username = request.getParameter(“username”); 8: String password = request.getParameter(“password”); 9: float money=Float.parseFloat(request.getParameter(“money”)); 10: UsersVo vo = new UsersVo(); 11: vo.setUsername(username); 12: vo.setPassword(password); Stacktrace: org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:519) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:428) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) root cause java.lang.NullPointerException sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:991) java.lang.Float.parseFloat(Float.java:422) org.apache.jsp.register_jsp._jspService(register_jsp.java:65) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:386) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) note The full stack trace of the root cause is available in the Apache Tomcat/6.0.32 logs.
10分	float money=Float.parseFloat(request.getParameter("money")); //此处request.getParameter("money") ==null,所以 java.lang.NullPointerException，你 debug看一下是 //不是为空
1分	HTTP Status 500 – ——————————————————————————– type Exception report message description The server encountered an internal error () that prevented it from fulfilling this request. exception org.apache.jasper.JasperException: java.lang.NullPointerException org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:522) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:416) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:337) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) root cause java.lang.NullPointerException org.apache.jsp.index_jsp._jspService(index_jsp.java:299) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:337) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) note The full stack trace of the root cause is available in the Apache Tomcat/6.0.16 logs. 这个怎么解决啊？
1分	求解，我也遇到这种问题
8分	register.jsp at line 9 java.lang.NullPointerException，找关键错误信息，明显是 Float.parseFloat()的时候报的错，你String moneys=request.getParameter(“money”); 打印一下moneys 看看有没有值，
	我也遇到这个问题，我用的是struts2+hibernate做的 jsp项目，你解决这个问题没有，有的话说一声
	引用 7 楼 u010962671 的回复: 我也遇到这个问题，我用的是struts2+hibernate做的 jsp项目，你解决这个问题没有，有的话说一声解决了么？我也遇到了这个问题，求解啊
	首先用request.getParamseter(“”)获取String类型的值，然后判断是否为null,如果为null,float.parfloat()会报空指针异常和数据转换异常的，要先判断获取的值是否为null
	求解这个类容
	楼主我已经改了密码和用户名了可是还是出现求教求教