# include <stdio.h>
# define N 100
char htoi(char s[]);
int main()
{
char a[N];
printf(“请输入十六进制数的字符串”);
gets(a);
htoi(a);
printf(“十进制数为:%d”, htoi(a));
return 0;
}
char htoi(char s[])
{
int i;
int n;
int sum;
sum = 0;
for (i = 0; s[i] != “”\0″”; i++)
{
if (s[i] >= “”0″” || s[i] <= “”9″”)
n = s[i] – “”0″”;
if (s[i] >= “”a”” || s[i] <= “”z””)
n = s[i] – 87;
if (s[i] >= “”A”” || s[i] <= “”Z””)
n = s[i] – 55;
sum = 16 * sum + n;
}
return sum;
}
帮本人看一下本人这代码错哪了,改代码是为了实现将十六进制数转化成十进制,0x为开头的十六进制数也可实现
# define N 100
char htoi(char s[]);
int main()
{
char a[N];
printf(“请输入十六进制数的字符串”);
gets(a);
htoi(a);
printf(“十进制数为:%d”, htoi(a));
return 0;
}
char htoi(char s[])
{
int i;
int n;
int sum;
sum = 0;
for (i = 0; s[i] != “”\0″”; i++)
{
if (s[i] >= “”0″” || s[i] <= “”9″”)
n = s[i] – “”0″”;
if (s[i] >= “”a”” || s[i] <= “”z””)
n = s[i] – 87;
if (s[i] >= “”A”” || s[i] <= “”Z””)
n = s[i] – 55;
sum = 16 * sum + n;
}
return sum;
}
帮本人看一下本人这代码错哪了,改代码是为了实现将十六进制数转化成十进制,0x为开头的十六进制数也可实现
解决方案:10分
仅供参考:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <locale.h>
int main() {
int i,v;
char bs[33];
char b[33];
char hs[9];
char h[9];
char s[4];
char *e;
// 十进制整数转二进制串;
i=1024;
ltoa(i,b,2);
sprintf(bs,"%032s",b);
printf("i=%d,bs=%s\n",i,bs);
// 十进制整数转十六进制串;
i=1024;
ltoa(i,h,16);
sprintf(hs,"%08s",h);
printf("i=%d,hs=%s\n",i,hs);
// 十六进制字符串转成十进制数
strcpy(hs,"00000400");
sscanf(hs,"%x",&i);
printf("hs=%s,i=%d\n",hs,i);
// 二进制字符串转化为十六进制字符串;
strcpy(bs,"00000000000000000000010000000000");
i=strtol(bs,&e,2);
ltoa(i,h,16);
sprintf(hs,"%08s",h);
printf("bs=%s,hs=%s\n",bs,hs);
// 二进制字符串转化为十进制数;
strcpy(bs,"00000000000000000000010000000000");
i=strtol(bs,&e,2);
printf("bs=%s,i=%d\n",bs,i);
// 十六进制字符串转成二进制串
strcpy(hs,"00000400");
sscanf(hs,"%x",&i);
ltoa(i,b,2);
sprintf(bs,"%032s",b);
printf("hs=%s,bs=%s\n",hs,bs);
// ASC\GBK字符串转十六进制串
strcpy(s,"a汉");
i=0;
while (1) {
if (0==s[i]) break;
sprintf(hs+i*2,"%02X",(unsigned char)s[i]);
i++;
}
setlocale(LC_ALL,"chs");
printf("s=%s,hs=%s\n",s,hs);
// 十六进制字符串转成汉字(GBK)及字符(ASC)
strcpy(hs,"61BABA");
i=0;
while (1) {
if (1!=sscanf(hs+i*2,"%2x",&v)) break;
s[i]=(char)v;
i++;
}
s[i]=0;
printf("hs=%s,s=%s\n",hs,s);
return 0;
}
//i=1024,bs=00000000000000000000010000000000
//i=1024,hs=00000400
//hs=00000400,i=1024
//bs=00000000000000000000010000000000,hs=00000400
//bs=00000000000000000000010000000000,i=1024
//hs=00000400,bs=00000000000000000000010000000000
//s=a汉,hs=61BABA
//hs=61BABA,s=a汉
解决方案:10分
if (s[i] >= “”0″” || s[i] <= “”9″”)
应该是用&&而不是 || 吧,其他几个if中的也对应改了
应该是用&&而不是 || 吧,其他几个if中的也对应改了
解决方案:20分
另外,htoi的返回值应该是int不是char吧
# include <stdio.h>
# define N 100
int htoi(char s[]);
int main()
{
char a[N];
printf("请输入十六进制数的字符串");
gets(a);
htoi(a);
printf("十进制数为:%d", htoi(a));
return 0;
}
int htoi(char s[])
{
int i;
int n;
int sum;
sum = 0;
for (i = 0; s[i] != ""\0""; i++)
{
if (s[i] >= ""0"" && s[i] <= ""9"")
n = s[i] - ""0"";
else if (s[i] >= ""a"" && s[i] <= ""z"")
n = s[i] - 87;
else if (s[i] >= ""A"" && s[i] <= ""Z"")
n = s[i] - 55;
sum = 16 * sum + n;
}
return sum;
}