客户端代码：

            var client = new ConnectionClient.AsyncBinarySocketClient(8192, 8192, 3000, 3000);
            client.RegisterServerNode("1122", new System.Net.IPEndPoint(System.Net.IPAddress.Parse("127.0.0.1"), 8888));
            byte[] bytes = null;
            string str = "njyang110"+"\t"+"123456";
            bytes = Encoding.Unicode.GetBytes(ConnectionBase.SerializeHelper.StringToBinaryString(str));
            for (int i = 0; i < 12; i++)
            {
                client.Send("Login", bytes, res => BitConverter.ToInt32(res.Buffer, 0)).ContinueWith(c =>
                {
                    if (c.IsFaulted)
                    {
                        Console.WriteLine(c.Exception.ToString());
                        return;
                    }
                });
                System.Threading.Thread.Sleep(50);
            }
            client.UnRegisterServerNode("1122");
            client.Stop();
            Console.ReadLine();

上面的代码 可以把消息循环发送完成，假如把for循环往上面移动一层 ，只能发送成功一次消息 然后就就开始超时了。客户端有做短线重新链接的功能，但是也是现实超时。请指点这是问什么呢
修改后的代码如下【修改后超时】

            for (int i = 0; i < 1200; i++)
            {
                var client = new ConnectionClient.AsyncBinarySocketClient(8192, 8192, 3000, 3000);
                client.RegisterServerNode("主服务器", new System.Net.IPEndPoint(System.Net.IPAddress.Parse("127.0.0.1"), 8401));
                byte[] bytes = null;
                string str = "njyang110"+"\t"+"123456";
                bytes = Encoding.Unicode.GetBytes(ConnectionBase.SerializeHelper.StringToBinaryString(str));
       
                client.Send("Login", bytes, res => BitConverter.ToInt32(res.Buffer, 0)).ContinueWith(c =>
                {
                    if (c.IsFaulted)
                    {
                        Console.WriteLine(c.Exception.ToString());
                        return;
                    }
                });
                System.Threading.Thread.Sleep(50);
                client.UnRegisterServerNode("主服务器");
                client.Stop();
            }
            Console.ReadLine();