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用c语言写一个函数把十进制转换成十六进制 |
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#include “stdio.h”
int main() { int num=0; int a[100]; int i=0; int m=0; int yushu; char hex[16]={“”0″”,””1″”,””2″”,””3″”,””4″”,””5″”,””6″”,””7″”,””8″”,””9″”,””A””,””B””,””C””,””D””,””E””,””F””}; printf(“请输入一个十进制整数:”); scanf(“%d”,&num); while(num>0) { yushu=num%16; a[i++]=yushu; num=num/16; } } 哈哈 简单易懂 |
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输入和输出分别是什么?
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试一下就知道,可以得到正确结果 |
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| 17分 |
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <locale.h>
int main() {
int i,v;
char bs[33];
char b[33];
char hs[9];
char h[9];
char s[4];
char *e;
// 十进制整数转二进制串;
i=1024;
ltoa(i,b,2);
sprintf(bs,"%032s",b);
printf("i=%d,bs=%s\n",i,bs);
// 十进制整数转十六进制串;
i=1024;
ltoa(i,h,16);
sprintf(hs,"%08s",h);
printf("i=%d,hs=%s\n",i,hs);
// 十六进制字符串转成十进制数
strcpy(hs,"00000400");
sscanf(hs,"%x",&i);
printf("hs=%s,i=%d\n",hs,i);
// 二进制字符串转化为十六进制字符串;
strcpy(bs,"00000000000000000000010000000000");
i=strtol(bs,&e,2);
ltoa(i,h,16);
sprintf(hs,"%08s",h);
printf("bs=%s,hs=%s\n",bs,hs);
// 二进制字符串转化为十进制数;
strcpy(bs,"00000000000000000000010000000000");
i=strtol(bs,&e,2);
printf("bs=%s,i=%d\n",bs,i);
// 十六进制字符串转成二进制串
strcpy(hs,"00000400");
sscanf(hs,"%x",&i);
ltoa(i,b,2);
sprintf(bs,"%032s",b);
printf("hs=%s,bs=%s\n",hs,bs);
// ASC\GBK字符串转十六进制串
strcpy(s,"a汉");
i=0;
while (1) {
if (0==s[i]) break;
sprintf(hs+i*2,"%02X",(unsigned char)s[i]);
i++;
}
setlocale(LC_ALL,"chs");
printf("s=%s,hs=%s\n",s,hs);
// 十六进制字符串转成汉字(GBK)及字符(ASC)
strcpy(hs,"61BABA");
i=0;
while (1) {
if (1!=sscanf(hs+i*2,"%2x",&v)) break;
s[i]=(char)v;
i++;
}
s[i]=0;
printf("hs=%s,s=%s\n",hs,s);
return 0;
}
//i=1024,bs=00000000000000000000010000000000
//i=1024,hs=00000400
//hs=00000400,i=1024
//bs=00000000000000000000010000000000,hs=00000400
//bs=00000000000000000000010000000000,i=1024
//hs=00000400,bs=00000000000000000000010000000000
//s=a汉,hs=61BABA
//hs=61BABA,s=a汉
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char pcDec[10]=”123456″;
char pcHex[100]; int iVal; //scanf(“%d”, &iVal); //从键盘输入。 printf(“%d\n%x\n”, iVal, iVal); //分别以10进度和16进制输出到屏幕。 sprintf(pcHex, “%d\n%x\n”, iVal, iVal); //分别以10进度和16进制输出到字符串中。 |
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| 3分 |
#include <stdio.h>
union decompose{
int integer;
struct{
unsigned int hex0 : 4;
unsigned int hex1 : 4;
unsigned int hex2 : 4;
unsigned int hex3 : 4;
unsigned int hex4 : 4;
unsigned int hex5 : 4;
unsigned int hex6 : 4;
unsigned int hex7 : 4;
}hex4;
};
/* 此宏定义不能用于循环,即n不能是变量,只能是数字
* 因此比较适用与零散获取位状态或者字节状态
*/
#define GETHEX(x, n) (((union decompose){.integer = x}).hex4.hex##n)
void test_getx(int tmp)
{
printf("%X", GETHEX(tmp, 0));
printf("%X", GETHEX(tmp, 1));
printf("%X", GETHEX(tmp, 2));
printf("%X", GETHEX(tmp, 3));
printf("%X", GETHEX(tmp, 4));
printf("%X", GETHEX(tmp, 5));
printf("%X", GETHEX(tmp, 6));
printf("%X\n", GETHEX(tmp, 7));
}
int main()
{
test_getx(100);
return 0;
}
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搞不懂你要转啥。。。。
整数类型计算机存储本身就是16进制的,有什么转换必要? |
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我的意思和7楼的差不多,输入和输出到底是什么?是字符串还是整型数啊,必须说清楚 |
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上面的连接错了,下面这个可用。
http://download.csdn.net/detail/allenemo/6487471 |
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这个是1000以下十进制转化十六进制的C程序,根据这个别的就不难了~~~~
#include<stdio.h> |
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如此多的解法。。。佩服佩服,谢谢
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